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Rupal Nandanwar
(@rupal_nandanwar)
New Member

In an examination, the maximum marks for each of the three papers is 50 each. The maximum
marks for the fourth paper is 100. Find the number of ways with which a student can score 60%
marks in aggregate.

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Topic starter Posted : 29/07/2021 2:08 pm
Rahul Singh
(@rahul)
Admin

Let a be marks that he loses in section A

Marks obtained + marks lost =50

a+A=50, a=50−A

Similar , b=50−B

C=50−C, d=100−D

A+B+C+D=150

a+b+c+d=100

100 Identical marks 4 variables

100+4−1 C 4−1 = 103!/(100!×3!) =(101×102×103)/(3×2) =101×103×17 =176851

subtracting  case (a=51.......100)

=3×52!/(49!×3!)

=66300

Final Answer : 176851 – 66300 =  110551

 

I hope this helps!

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Posted : 08/10/2021 11:49 am
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